Base | Representation |
---|---|
bin | 1000001101101001101… |
… | …0010111111000001111 |
3 | 111111012201202022222021 |
4 | 2003122122113320033 |
5 | 4302434421100421 |
6 | 144453313231011 |
7 | 13123446155464 |
oct | 2033232277017 |
9 | 444181668867 |
10 | 141103300111 |
11 | 54929152914 |
12 | 2341b262467 |
13 | 103c9329ab7 |
14 | 6b87d8966b |
15 | 3a0ca0a341 |
hex | 20da697e0f |
141103300111 has 4 divisors (see below), whose sum is σ = 141187845400. Its totient is φ = 141018754824.
The previous prime is 141103300081. The next prime is 141103300141. The reversal of 141103300111 is 111003301141.
It is a semiprime because it is the product of two primes.
It is an interprime number because it is at equal distance from previous prime (141103300081) and next prime (141103300141).
It is a cyclic number.
It is not a de Polignac number, because 141103300111 - 221 = 141101202959 is a prime.
It is a super-2 number, since 2×1411033001112 (a number of 23 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (141103300141) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 42270141 + ... + 42273478.
It is an arithmetic number, because the mean of its divisors is an integer number (35296961350).
Almost surely, 2141103300111 is an apocalyptic number.
141103300111 is a deficient number, since it is larger than the sum of its proper divisors (84545289).
141103300111 is an equidigital number, since it uses as much as digits as its factorization.
141103300111 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 84545288.
The product of its (nonzero) digits is 36, while the sum is 16.
Adding to 141103300111 its reverse (111003301141), we get a palindrome (252106601252).
The spelling of 141103300111 in words is "one hundred forty-one billion, one hundred three million, three hundred thousand, one hundred eleven".
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