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141104044057 is a prime number
BaseRepresentation
bin1000001101101001110…
…1001101100000011001
3111111012210011010110211
42003122131031200121
54302440113402212
6144453341211121
713123455404434
oct2033235154031
9444183133424
10141104044057
1154929610849
122341b560aa1
13103c952a5c2
146b8810081b
153a0cb059a7
hex20da74d819

141104044057 has 2 divisors, whose sum is σ = 141104044058. Its totient is φ = 141104044056.

The previous prime is 141104044001. The next prime is 141104044087. The reversal of 141104044057 is 750440401141.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 82431577881 + 58672466176 = 287109^2 + 242224^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-141104044057 is a prime.

It is not a weakly prime, because it can be changed into another prime (141104044087) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70552022028 + 70552022029.

It is an arithmetic number, because the mean of its divisors is an integer number (70552022029).

Almost surely, 2141104044057 is an apocalyptic number.

It is an amenable number.

141104044057 is a deficient number, since it is larger than the sum of its proper divisors (1).

141104044057 is an equidigital number, since it uses as much as digits as its factorization.

141104044057 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 8960, while the sum is 31.

Adding to 141104044057 its reverse (750440401141), we get a palindrome (891544445198).

The spelling of 141104044057 in words is "one hundred forty-one billion, one hundred four million, forty-four thousand, fifty-seven".