14110410013 has 4 divisors (see below), whose sum is σ = 16126182880. Its totient is φ = 12094637148.

The previous prime is 14110409993. The next prime is 14110410029. The reversal of 14110410013 is 31001401141.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-14110410013 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14110416013) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1007886423 + ... + 1007886436.

It is an arithmetic number, because the mean of its divisors is an integer number (4031545720).

Almost surely, 2^14110410013 is an apocalyptic number.

It is an amenable number.

14110410013 is a deficient number, since it is larger than the sum of its proper divisors (2015772867).

14110410013 is an equidigital number, since it uses as much as digits as its factorization.

14110410013 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2015772866.

The product of its (nonzero) digits is 48, while the sum is 16.

Adding to 14110410013 its reverse (31001401141), we get a palindrome (45111811154).

The spelling of 14110410013 in words is "fourteen billion, one hundred ten million, four hundred ten thousand, thirteen".