Base | Representation |
---|---|
bin | 1000001101101001110… |
… | …1100011100010111010 |
3 | 111111012210022201022021 |
4 | 2003122131203202322 |
5 | 4302440124244310 |
6 | 144453343145054 |
7 | 13123456231555 |
oct | 2033235434272 |
9 | 444183281267 |
10 | 141104134330 |
11 | 54929672655 |
12 | 2341b5a518a |
13 | 103c955c713 |
14 | 6b8812569c |
15 | 3a0cb225da |
hex | 20da7638ba |
141104134330 has 32 divisors (see below), whose sum is σ = 258402711168. Its totient is φ = 55462286400.
The previous prime is 141104134267. The next prime is 141104134343. The reversal of 141104134330 is 33431401141.
It is a happy number.
141104134330 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a junction number, because it is equal to n+sod(n) for n = 141104134295 and 141104134304.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 516729 + ... + 741091.
It is an arithmetic number, because the mean of its divisors is an integer number (8075084724).
Almost surely, 2141104134330 is an apocalyptic number.
141104134330 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
141104134330 is a deficient number, since it is larger than the sum of its proper divisors (117298576838).
141104134330 is a wasteful number, since it uses less digits than its factorization.
141104134330 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 225462.
The product of its (nonzero) digits is 1728, while the sum is 25.
Adding to 141104134330 its reverse (33431401141), we get a palindrome (174535535471).
The spelling of 141104134330 in words is "one hundred forty-one billion, one hundred four million, one hundred thirty-four thousand, three hundred thirty".
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