Base | Representation |
---|---|
bin | 1000001101101010010… |
… | …0111000100010110011 |
3 | 111111012220221022110001 |
4 | 2003122210320202303 |
5 | 4302441122232342 |
6 | 144453452250431 |
7 | 13123511452315 |
oct | 2033244704263 |
9 | 444186838401 |
10 | 141106055347 |
11 | 5492a764974 |
12 | 23420170a17 |
13 | 103c9a82c0a |
14 | 6b884a57b5 |
15 | 3a0cda18b7 |
hex | 20da9388b3 |
141106055347 has 4 divisors (see below), whose sum is σ = 145657863616. Its totient is φ = 136554247080.
The previous prime is 141106055339. The next prime is 141106055407. The reversal of 141106055347 is 743550601141.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 743550601141 = 37 ⋅20095962193.
It is a cyclic number.
It is not a de Polignac number, because 141106055347 - 23 = 141106055339 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (141106050347) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2275904088 + ... + 2275904149.
It is an arithmetic number, because the mean of its divisors is an integer number (36414465904).
Almost surely, 2141106055347 is an apocalyptic number.
141106055347 is a deficient number, since it is larger than the sum of its proper divisors (4551808269).
141106055347 is an equidigital number, since it uses as much as digits as its factorization.
141106055347 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4551808268.
The product of its (nonzero) digits is 50400, while the sum is 37.
Adding to 141106055347 its reverse (743550601141), we get a palindrome (884656656488).
The spelling of 141106055347 in words is "one hundred forty-one billion, one hundred six million, fifty-five thousand, three hundred forty-seven".
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