Base | Representation |
---|---|
bin | 1100110101010111100110… |
… | …1111011011001001001011 |
3 | 1211221222222112220101212222 |
4 | 3031111321233123021023 |
5 | 3322143322032324233 |
6 | 50002301501324255 |
7 | 2654325661216136 |
oct | 315257157331113 |
9 | 54858875811788 |
10 | 14111010042443 |
11 | 455049a328616 |
12 | 16ba98486668b |
13 | 7b487c795cb2 |
14 | 36ad9585521d |
15 | 1970d6a0c898 |
hex | cd579bdb24b |
14111010042443 has 2 divisors, whose sum is σ = 14111010042444. Its totient is φ = 14111010042442.
The previous prime is 14111010042427. The next prime is 14111010042487. The reversal of 14111010042443 is 34424001011141.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 14111010042443 - 24 = 14111010042427 is a prime.
It is a super-2 number, since 2×141110100424432 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (14111010042343) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7055505021221 + 7055505021222.
It is an arithmetic number, because the mean of its divisors is an integer number (7055505021222).
Almost surely, 214111010042443 is an apocalyptic number.
14111010042443 is a deficient number, since it is larger than the sum of its proper divisors (1).
14111010042443 is an equidigital number, since it uses as much as digits as its factorization.
14111010042443 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1536, while the sum is 26.
Adding to 14111010042443 its reverse (34424001011141), we get a palindrome (48535011053584).
The spelling of 14111010042443 in words is "fourteen trillion, one hundred eleven billion, ten million, forty-two thousand, four hundred forty-three".
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