141110108540213 has 4 divisors (see below), whose sum is σ = 141118089447468. Its totient is φ = 141102127632960.

The previous prime is 141110108540209. The next prime is 141110108540231. The reversal of 141110108540213 is 312045801011141.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 51707921035684 + 89402187504529 = 7190822^2 + 9455273^2 .

It is a cyclic number.

It is not a de Polignac number, because 141110108540213 - 2² = 141110108540209 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 141110108540213.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (141110102540213) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3990427106 + ... + 3990462467.

It is an arithmetic number, because the mean of its divisors is an integer number (35279522361867).

Almost surely, 2^{141110108540213} is an apocalyptic number.

It is an amenable number.

141110108540213 is a deficient number, since it is larger than the sum of its proper divisors (7980907255).

141110108540213 is an equidigital number, since it uses as much as digits as its factorization.

141110108540213 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 7980907254.

The product of its (nonzero) digits is 3840, while the sum is 32.

Adding to 141110108540213 its reverse (312045801011141), we get a palindrome (453155909551354).

The spelling of 141110108540213 in words is "one hundred forty-one trillion, one hundred ten billion, one hundred eight million, five hundred forty thousand, two hundred thirteen".