Base | Representation |
---|---|
bin | 1100110101010111101010… |
… | …1010100001010101100111 |
3 | 1211222000000122001110201212 |
4 | 3031111322222201111213 |
5 | 3322143340014044221 |
6 | 50002303213342035 |
7 | 2654326240001006 |
oct | 315257252412547 |
9 | 54860018043655 |
10 | 14111025534311 |
11 | 45504a8049912 |
12 | 16ba989a9791b |
13 | 7b4882a5b494 |
14 | 36ad97928c3d |
15 | 1970d806cb5b |
hex | cd57aaa1567 |
14111025534311 has 2 divisors, whose sum is σ = 14111025534312. Its totient is φ = 14111025534310.
The previous prime is 14111025534301. The next prime is 14111025534407. The reversal of 14111025534311 is 11343552011141.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-14111025534311 is a prime.
It is a Sophie Germain prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14111025534301) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7055512767155 + 7055512767156.
It is an arithmetic number, because the mean of its divisors is an integer number (7055512767156).
Almost surely, 214111025534311 is an apocalyptic number.
14111025534311 is a deficient number, since it is larger than the sum of its proper divisors (1).
14111025534311 is an equidigital number, since it uses as much as digits as its factorization.
14111025534311 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 7200, while the sum is 32.
Adding to 14111025534311 its reverse (11343552011141), we get a palindrome (25454577545452).
The spelling of 14111025534311 in words is "fourteen trillion, one hundred eleven billion, twenty-five million, five hundred thirty-four thousand, three hundred eleven".
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