14111025535051 has 2 divisors, whose sum is σ = 14111025535052. Its totient is φ = 14111025535050.

The previous prime is 14111025535049. The next prime is 14111025535109. The reversal of 14111025535051 is 15053552011141.

14111025535051 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 14111025535051 - 2¹ = 14111025535049 is a prime.

It is a super-2 number, since 2×14111025535051² (a number of 27 digits) contains 22 as substring.

Together with 14111025535049, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 14111025534998 and 14111025535016.

It is not a weakly prime, because it can be changed into another prime (14111025535001) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7055512767525 + 7055512767526.

It is an arithmetic number, because the mean of its divisors is an integer number (7055512767526).

Almost surely, 2^{14111025535051} is an apocalyptic number.

14111025535051 is a deficient number, since it is larger than the sum of its proper divisors (1).

14111025535051 is an equidigital number, since it uses as much as digits as its factorization.

14111025535051 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 15000, while the sum is 34.

Adding to 14111025535051 its reverse (15053552011141), we get a palindrome (29164577546192).

The spelling of 14111025535051 in words is "fourteen trillion, one hundred eleven billion, twenty-five million, five hundred thirty-five thousand, fifty-one".