14111030121233 has 2 divisors, whose sum is σ = 14111030121234. Its totient is φ = 14111030121232.

The previous prime is 14111030121203. The next prime is 14111030121241. The reversal of 14111030121233 is 33212103011141.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 13804145144449 + 306884976784 = 3715393^2 + 553972^2 .

It is a cyclic number.

It is not a de Polignac number, because 14111030121233 - 2²² = 14111025926929 is a prime.

It is a super-3 number, since 3×14111030121233³ (a number of 40 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 14111030121199 and 14111030121208.

It is not a weakly prime, because it can be changed into another prime (14111030121203) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7055515060616 + 7055515060617.

It is an arithmetic number, because the mean of its divisors is an integer number (7055515060617).

Almost surely, 2^{14111030121233} is an apocalyptic number.

It is an amenable number.

14111030121233 is a deficient number, since it is larger than the sum of its proper divisors (1).

14111030121233 is an equidigital number, since it uses as much as digits as its factorization.

14111030121233 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 432, while the sum is 23.

Adding to 14111030121233 its reverse (33212103011141), we get a palindrome (47323133132374).

The spelling of 14111030121233 in words is "fourteen trillion, one hundred eleven billion, thirty million, one hundred twenty-one thousand, two hundred thirty-three".