14111034125051 has 2 divisors, whose sum is σ = 14111034125052. Its totient is φ = 14111034125050.

The previous prime is 14111034124987. The next prime is 14111034125053. The reversal of 14111034125051 is 15052143011141.

It is a strong prime.

It is an emirp because it is prime and its reverse (15052143011141) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 14111034125051 - 2⁶ = 14111034124987 is a prime.

It is a super-2 number, since 2×14111034125051² (a number of 27 digits) contains 22 as substring.

Together with 14111034125053, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (14111034125053) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7055517062525 + 7055517062526.

It is an arithmetic number, because the mean of its divisors is an integer number (7055517062526).

Almost surely, 2^{14111034125051} is an apocalyptic number.

14111034125051 is a deficient number, since it is larger than the sum of its proper divisors (1).

14111034125051 is an equidigital number, since it uses as much as digits as its factorization.

14111034125051 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2400, while the sum is 29.

Adding to 14111034125051 its reverse (15052143011141), we get a palindrome (29163177136192).

The spelling of 14111034125051 in words is "fourteen trillion, one hundred eleven billion, thirty-four million, one hundred twenty-five thousand, fifty-one".