14111034125141 has 4 divisors (see below), whose sum is σ = 14342362553484. Its totient is φ = 13879705696800.

The previous prime is 14111034125099. The next prime is 14111034125179. The reversal of 14111034125141 is 14152143011141.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 1120307934916 + 12990726190225 = 1058446^2 + 3604265^2 .

It is a cyclic number.

It is not a de Polignac number, because 14111034125141 - 2¹⁴ = 14111034108757 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14111034121141) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 115664214080 + ... + 115664214201.

It is an arithmetic number, because the mean of its divisors is an integer number (3585590638371).

Almost surely, 2^{14111034125141} is an apocalyptic number.

It is an amenable number.

14111034125141 is a deficient number, since it is larger than the sum of its proper divisors (231328428343).

14111034125141 is an equidigital number, since it uses as much as digits as its factorization.

14111034125141 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 231328428342.

The product of its (nonzero) digits is 1920, while the sum is 29.

Adding to 14111034125141 its reverse (14152143011141), we get a palindrome (28263177136282).

The spelling of 14111034125141 in words is "fourteen trillion, one hundred eleven billion, thirty-four million, one hundred twenty-five thousand, one hundred forty-one".