Base | Representation |
---|---|
bin | 1100110101010111111100… |
… | …0011101011111101111101 |
3 | 1211222000012202202010100221 |
4 | 3031111333003223331331 |
5 | 3322144012401142232 |
6 | 50002314405221341 |
7 | 2654331123331222 |
oct | 315257703537575 |
9 | 54860182663327 |
10 | 14111099240317 |
11 | 4550535711272 |
12 | 16ba9aa701851 |
13 | 7b48950c6ac1 |
14 | 36ada3633949 |
15 | 1970de77b897 |
hex | cd57f0ebf7d |
14111099240317 has 2 divisors, whose sum is σ = 14111099240318. Its totient is φ = 14111099240316.
The previous prime is 14111099240291. The next prime is 14111099240351. The reversal of 14111099240317 is 71304299011141.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 10321948902841 + 3789150337476 = 3212779^2 + 1946574^2 .
It is a cyclic number.
It is not a de Polignac number, because 14111099240317 - 215 = 14111099207549 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14111099244317) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7055549620158 + 7055549620159.
It is an arithmetic number, because the mean of its divisors is an integer number (7055549620159).
Almost surely, 214111099240317 is an apocalyptic number.
It is an amenable number.
14111099240317 is a deficient number, since it is larger than the sum of its proper divisors (1).
14111099240317 is an equidigital number, since it uses as much as digits as its factorization.
14111099240317 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 54432, while the sum is 43.
The spelling of 14111099240317 in words is "fourteen trillion, one hundred eleven billion, ninety-nine million, two hundred forty thousand, three hundred seventeen".
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