Base | Representation |
---|---|
bin | 1100110101010111111101… |
… | …0011101011111101110011 |
3 | 1211222000020001122012212011 |
4 | 3031111333103223331303 |
5 | 3322144014434401421 |
6 | 50002315035143351 |
7 | 2654331204100411 |
oct | 315257723537563 |
9 | 54860201565764 |
10 | 14111103434611 |
11 | 4550538016527 |
12 | 16ba9abba4b57 |
13 | 7b4895c34c31 |
14 | 36ada40062b1 |
15 | 1970ded094e1 |
hex | cd57f4ebf73 |
14111103434611 has 2 divisors, whose sum is σ = 14111103434612. Its totient is φ = 14111103434610.
The previous prime is 14111103434591. The next prime is 14111103434621. The reversal of 14111103434611 is 11643430111141.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 14111103434611 - 225 = 14111069880179 is a prime.
It is a super-3 number, since 3×141111034346113 (a number of 40 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (14111103434621) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7055551717305 + 7055551717306.
It is an arithmetic number, because the mean of its divisors is an integer number (7055551717306).
Almost surely, 214111103434611 is an apocalyptic number.
14111103434611 is a deficient number, since it is larger than the sum of its proper divisors (1).
14111103434611 is an equidigital number, since it uses as much as digits as its factorization.
14111103434611 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3456, while the sum is 31.
Adding to 14111103434611 its reverse (11643430111141), we get a palindrome (25754533545752).
The spelling of 14111103434611 in words is "fourteen trillion, one hundred eleven billion, one hundred three million, four hundred thirty-four thousand, six hundred eleven".
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