141112011013 has 4 divisors (see below), whose sum is σ = 142812155808. Its totient is φ = 139411866220.

The previous prime is 141112010999. The next prime is 141112011037. The reversal of 141112011013 is 310110211141.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-141112011013 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (141112011043) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 850072273 + ... + 850072438.

It is an arithmetic number, because the mean of its divisors is an integer number (35703038952).

Almost surely, 2^141112011013 is an apocalyptic number.

It is an amenable number.

141112011013 is a deficient number, since it is larger than the sum of its proper divisors (1700144795).

141112011013 is an equidigital number, since it uses as much as digits as its factorization.

141112011013 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1700144794.

The product of its (nonzero) digits is 24, while the sum is 16.

Adding to 141112011013 its reverse (310110211141), we get a palindrome (451222222154).

The spelling of 141112011013 in words is "one hundred forty-one billion, one hundred twelve million, eleven thousand, thirteen".