1411120124143 has 4 divisors (see below), whose sum is σ = 1411179989128. Its totient is φ = 1411060259160.

The previous prime is 1411120124131. The next prime is 1411120124173. The reversal of 1411120124143 is 3414210211141.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1411120124143 is a prime.

It is a super-2 number, since 2×1411120124143² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1411120124173) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 29897121 + ... + 29944282.

It is an arithmetic number, because the mean of its divisors is an integer number (352794997282).

Almost surely, 2^{1411120124143} is an apocalyptic number.

1411120124143 is a deficient number, since it is larger than the sum of its proper divisors (59864985).

1411120124143 is an equidigital number, since it uses as much as digits as its factorization.

1411120124143 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 59864984.

The product of its (nonzero) digits is 768, while the sum is 25.

Adding to 1411120124143 its reverse (3414210211141), we get a palindrome (4825330335284).

The spelling of 1411120124143 in words is "one trillion, four hundred eleven billion, one hundred twenty million, one hundred twenty-four thousand, one hundred forty-three".