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141112041433 = 1117971666857
BaseRepresentation
bin1000001101101011101…
…1101101111111011001
3111111020100012102210221
42003122323231333121
54302444140311213
6144454224440041
713123613363416
oct2033273557731
9444210172727
10141112041433
1154933083350
1223422179021
13103cb09a78c
146b891c310d
153a0d68538d
hex20daeedfd9

141112041433 has 8 divisors (see below), whose sum is σ = 154800413280. Its totient is φ = 127567003680.

The previous prime is 141112041397. The next prime is 141112041443. The reversal of 141112041433 is 334140211141.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 141112041433 - 217 = 141111910361 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 141112041398 and 141112041407.

It is not an unprimeable number, because it can be changed into a prime (141112041443) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 35831460 + ... + 35835397.

It is an arithmetic number, because the mean of its divisors is an integer number (19350051660).

Almost surely, 2141112041433 is an apocalyptic number.

It is an amenable number.

141112041433 is a deficient number, since it is larger than the sum of its proper divisors (13688371847).

141112041433 is a wasteful number, since it uses less digits than its factorization.

141112041433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 71667047.

The product of its (nonzero) digits is 1152, while the sum is 25.

Adding to 141112041433 its reverse (334140211141), we get a palindrome (475252252574).

The spelling of 141112041433 in words is "one hundred forty-one billion, one hundred twelve million, forty-one thousand, four hundred thirty-three".

Divisors: 1 11 179 1969 71666857 788335427 12828367403 141112041433