Base | Representation |
---|---|
bin | 1000001101101011110… |
… | …0011010101001100001 |
3 | 111111020100112201201202 |
4 | 2003122330122221201 |
5 | 4302444212134403 |
6 | 144454232410545 |
7 | 13123615054622 |
oct | 2033274325141 |
9 | 444210481652 |
10 | 141112224353 |
11 | 54933198821 |
12 | 23422246a55 |
13 | 103cb132b09 |
14 | 6b8922da49 |
15 | 3a0d6be688 |
hex | 20daf1aa61 |
141112224353 has 2 divisors, whose sum is σ = 141112224354. Its totient is φ = 141112224352.
The previous prime is 141112224313. The next prime is 141112224361. The reversal of 141112224353 is 353422211141.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 137810227984 + 3301996369 = 371228^2 + 57463^2 .
It is an emirp because it is prime and its reverse (353422211141) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 141112224353 - 26 = 141112224289 is a prime.
It is not a weakly prime, because it can be changed into another prime (141112224313) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70556112176 + 70556112177.
It is an arithmetic number, because the mean of its divisors is an integer number (70556112177).
Almost surely, 2141112224353 is an apocalyptic number.
It is an amenable number.
141112224353 is a deficient number, since it is larger than the sum of its proper divisors (1).
141112224353 is an equidigital number, since it uses as much as digits as its factorization.
141112224353 is an evil number, because the sum of its binary digits is even.
The product of its digits is 5760, while the sum is 29.
Adding to 141112224353 its reverse (353422211141), we get a palindrome (494534435494).
The spelling of 141112224353 in words is "one hundred forty-one billion, one hundred twelve million, two hundred twenty-four thousand, three hundred fifty-three".
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