Base | Representation |
---|---|
bin | 1000001101101011110… |
… | …0110000000011000001 |
3 | 111111020100201011221222 |
4 | 2003122330300003001 |
5 | 4302444222441001 |
6 | 144454234324425 |
7 | 13123615601303 |
oct | 2033274600301 |
9 | 444210634858 |
10 | 141112312001 |
11 | 54933248661 |
12 | 23422289715 |
13 | 103cb16398b |
14 | 6b89253973 |
15 | 3a0d6da61b |
hex | 20daf300c1 |
141112312001 has 4 divisors (see below), whose sum is σ = 141117389232. Its totient is φ = 141107234772.
The previous prime is 141112311979. The next prime is 141112312043. The reversal of 141112312001 is 100213211141.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-141112312001 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (141112312501) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2496695 + ... + 2552588.
It is an arithmetic number, because the mean of its divisors is an integer number (35279347308).
Almost surely, 2141112312001 is an apocalyptic number.
It is an amenable number.
141112312001 is a deficient number, since it is larger than the sum of its proper divisors (5077231).
141112312001 is an equidigital number, since it uses as much as digits as its factorization.
141112312001 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 5077230.
The product of its (nonzero) digits is 48, while the sum is 17.
Adding to 141112312001 its reverse (100213211141), we get a palindrome (241325523142).
The spelling of 141112312001 in words is "one hundred forty-one billion, one hundred twelve million, three hundred twelve thousand, one".
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