1411123211111 has 2 divisors, whose sum is σ = 1411123211112. Its totient is φ = 1411123211110.

The previous prime is 1411123211083. The next prime is 1411123211159. The reversal of 1411123211111 is 1111123211141.

It is a m-pointer prime, because the next prime (1411123211159) can be obtained adding 1411123211111 to its product of digits (48).

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 1411123211111 - 2³⁸ = 1136245304167 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1411123211411) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 705561605555 + 705561605556.

It is an arithmetic number, because the mean of its divisors is an integer number (705561605556).

Almost surely, 2^{1411123211111} is an apocalyptic number.

1411123211111 is a deficient number, since it is larger than the sum of its proper divisors (1).

1411123211111 is an equidigital number, since it uses as much as digits as its factorization.

1411123211111 is an evil number, because the sum of its binary digits is even.

The product of its digits is 48, while the sum is 20.

Adding to 1411123211111 its reverse (1111123211141), we get a palindrome (2522246422252).

The spelling of 1411123211111 in words is "one trillion, four hundred eleven billion, one hundred twenty-three million, two hundred eleven thousand, one hundred eleven".