Base | Representation |
---|---|
bin | 10100100010001101100… |
… | …011110000110010001011 |
3 | 11222220100200012111122111 |
4 | 110202031203300302023 |
5 | 141104440301013103 |
6 | 3000132253403151 |
7 | 203643655044151 |
oct | 24421543606213 |
9 | 4886320174574 |
10 | 1411124235403 |
11 | 4a44aa92aa73 |
12 | 1a959a7994b7 |
13 | a30b74ac19c |
14 | 4c427bb93d1 |
15 | 26a8ea8e86d |
hex | 1488d8f0c8b |
1411124235403 has 2 divisors, whose sum is σ = 1411124235404. Its totient is φ = 1411124235402.
The previous prime is 1411124235379. The next prime is 1411124235431. The reversal of 1411124235403 is 3045324211141.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1411124235403 is a prime.
It is not a weakly prime, because it can be changed into another prime (1411124295403) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 705562117701 + 705562117702.
It is an arithmetic number, because the mean of its divisors is an integer number (705562117702).
Almost surely, 21411124235403 is an apocalyptic number.
1411124235403 is a deficient number, since it is larger than the sum of its proper divisors (1).
1411124235403 is an equidigital number, since it uses as much as digits as its factorization.
1411124235403 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 11520, while the sum is 31.
Adding to 1411124235403 its reverse (3045324211141), we get a palindrome (4456448446544).
The spelling of 1411124235403 in words is "one trillion, four hundred eleven billion, one hundred twenty-four million, two hundred thirty-five thousand, four hundred three".
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