Base | Representation |
---|---|
bin | 1100110101011000101100… |
… | …1110100111011110000111 |
3 | 1211222000201222222010210111 |
4 | 3031112023032213132013 |
5 | 3322144422134311241 |
6 | 50002350541533451 |
7 | 2654336153044366 |
oct | 315261316473607 |
9 | 54860658863714 |
10 | 14111303432071 |
11 | 455062a9a758a |
12 | 16baa46b74287 |
13 | 7b48c84bb021 |
14 | 36adc27c77dd |
15 | 197102662c81 |
hex | cd58b3a7787 |
14111303432071 has 2 divisors, whose sum is σ = 14111303432072. Its totient is φ = 14111303432070.
The previous prime is 14111303431999. The next prime is 14111303432123. The reversal of 14111303432071 is 17023430311141.
It is a strong prime.
It is an emirp because it is prime and its reverse (17023430311141) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 14111303432071 - 211 = 14111303430023 is a prime.
It is a super-2 number, since 2×141113034320712 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14111303430071) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7055651716035 + 7055651716036.
It is an arithmetic number, because the mean of its divisors is an integer number (7055651716036).
Almost surely, 214111303432071 is an apocalyptic number.
14111303432071 is a deficient number, since it is larger than the sum of its proper divisors (1).
14111303432071 is an equidigital number, since it uses as much as digits as its factorization.
14111303432071 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6048, while the sum is 31.
The spelling of 14111303432071 in words is "fourteen trillion, one hundred eleven billion, three hundred three million, four hundred thirty-two thousand, seventy-one".
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