141113433104221 has 4 divisors (see below), whose sum is σ = 148540455899200. Its totient is φ = 133686410309244.

The previous prime is 141113433104209. The next prime is 141113433104263. The reversal of 141113433104221 is 122401334311141.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 141113433104221 - 2²¹ = 141113431007069 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (141113433104291) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3713511397461 + ... + 3713511397498.

It is an arithmetic number, because the mean of its divisors is an integer number (37135113974800).

Almost surely, 2^{141113433104221} is an apocalyptic number.

It is an amenable number.

141113433104221 is a deficient number, since it is larger than the sum of its proper divisors (7427022794979).

141113433104221 is an equidigital number, since it uses as much as digits as its factorization.

141113433104221 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 7427022794978.

The product of its (nonzero) digits is 6912, while the sum is 31.

Adding to 141113433104221 its reverse (122401334311141), we get a palindrome (263514767415362).

The spelling of 141113433104221 in words is "one hundred forty-one trillion, one hundred thirteen billion, four hundred thirty-three million, one hundred four thousand, two hundred twenty-one".