Base | Representation |
---|---|
bin | 1100110101011001001000… |
… | …1100001010100110011010 |
3 | 1211222001001010202002111021 |
4 | 3031112102030022212122 |
5 | 3322200142034330132 |
6 | 50002410313153054 |
7 | 2654342101601302 |
oct | 315262214124632 |
9 | 54861033662437 |
10 | 14111420230042 |
11 | 455068a921633 |
12 | 16baa7a0bb78a |
13 | 7b4916763655 |
14 | 36add410c602 |
15 | 19710ca34997 |
hex | cd59230a99a |
14111420230042 has 8 divisors (see below), whose sum is σ = 21176660802132. Its totient is φ = 7052533296000.
The previous prime is 14111420230013. The next prime is 14111420230057. The reversal of 14111420230042 is 24003202411141.
It can be written as a sum of positive squares in 2 ways, for example, as 13910967927081 + 200452302961 = 3729741^2 + 447719^2 .
It is a sphenic number, since it is the product of 3 distinct primes.
It is a super-2 number, since 2×141114202300422 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 14111420229989 and 14111420230016.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1588403959 + ... + 1588412842.
Almost surely, 214111420230042 is an apocalyptic number.
14111420230042 is a deficient number, since it is larger than the sum of its proper divisors (7065240572090).
14111420230042 is a wasteful number, since it uses less digits than its factorization.
14111420230042 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3176819024.
The product of its (nonzero) digits is 1536, while the sum is 25.
Adding to 14111420230042 its reverse (24003202411141), we get a palindrome (38114622641183).
The spelling of 14111420230042 in words is "fourteen trillion, one hundred eleven billion, four hundred twenty million, two hundred thirty thousand, forty-two".
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