Base | Representation |
---|---|
bin | 1100110101011001011111… |
… | …0111010101011001101001 |
3 | 1211222001021202212212210012 |
4 | 3031112113313111121221 |
5 | 3322200340422320203 |
6 | 50002423553501305 |
7 | 2654344336032530 |
oct | 315262767253151 |
9 | 54861252785705 |
10 | 14111515432553 |
11 | 45507296366a0 |
12 | 16baaa5b71835 |
13 | 7b49303b75b6 |
14 | 36b002a11317 |
15 | 19711608cbd8 |
hex | cd597dd5669 |
14111515432553 has 24 divisors (see below), whose sum is σ = 18033155636160. Its totient is φ = 10727791171200.
The previous prime is 14111515432537. The next prime is 14111515432571. The reversal of 14111515432553 is 35523451511141.
It is not a de Polignac number, because 14111515432553 - 24 = 14111515432537 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (41).
It is a self number, because there is not a number n which added to its sum of digits gives 14111515432553.
It is not an unprimeable number, because it can be changed into a prime (14111515432153) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 54381698 + ... + 54640571.
It is an arithmetic number, because the mean of its divisors is an integer number (751381484840).
Almost surely, 214111515432553 is an apocalyptic number.
It is an amenable number.
14111515432553 is a deficient number, since it is larger than the sum of its proper divisors (3921640203607).
14111515432553 is a wasteful number, since it uses less digits than its factorization.
14111515432553 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 109022369 (or 109022328 counting only the distinct ones).
The product of its digits is 180000, while the sum is 41.
Adding to 14111515432553 its reverse (35523451511141), we get a palindrome (49634966943694).
The spelling of 14111515432553 in words is "fourteen trillion, one hundred eleven billion, five hundred fifteen million, four hundred thirty-two thousand, five hundred fifty-three".
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