14112024252133 has 4 divisors (see below), whose sum is σ = 14193596646828. Its totient is φ = 14030451857440.

The previous prime is 14112024252083. The next prime is 14112024252163. The reversal of 14112024252133 is 33125242021141.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 12197849621764 + 1914174630369 = 3492542^2 + 1383537^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-14112024252133 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 14112024252095 and 14112024252104.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14112024252163) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 40786197088 + ... + 40786197433.

It is an arithmetic number, because the mean of its divisors is an integer number (3548399161707).

Almost surely, 2^{14112024252133} is an apocalyptic number.

It is an amenable number.

14112024252133 is a deficient number, since it is larger than the sum of its proper divisors (81572394695).

14112024252133 is an equidigital number, since it uses as much as digits as its factorization.

14112024252133 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 81572394694.

The product of its (nonzero) digits is 11520, while the sum is 31.

Adding to 14112024252133 its reverse (33125242021141), we get a palindrome (47237266273274).

The spelling of 14112024252133 in words is "fourteen trillion, one hundred twelve billion, twenty-four million, two hundred fifty-two thousand, one hundred thirty-three".