14112112220031 has 8 divisors (see below), whose sum is σ = 21504171001984. Its totient is φ = 8064064125720.

The previous prime is 14112112219993. The next prime is 14112112220053. The reversal of 14112112220031 is 13002221121141.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 14112112220031 - 2¹⁴ = 14112112203647 is a prime.

It is a super-2 number, since 2×14112112220031² (a number of 27 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (21), and also a Moran number because the ratio is a prime number: 672005343811 = 14112112220031 / (1 + 4 + 1 + 1 + 2 + 1 + 1 + 2 + 2 + 2 + 0 + 0 + 3 + 1).

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14112112222031) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (31) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 336002671885 + ... + 336002671926.

It is an arithmetic number, because the mean of its divisors is an integer number (2688021375248).

Almost surely, 2^{14112112220031} is an apocalyptic number.

14112112220031 is a deficient number, since it is larger than the sum of its proper divisors (7392058781953).

14112112220031 is an equidigital number, since it uses as much as digits as its factorization.

14112112220031 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 672005343821.

The product of its (nonzero) digits is 192, while the sum is 21.

Adding to 14112112220031 its reverse (13002221121141), we get a palindrome (27114333341172).

The spelling of 14112112220031 in words is "fourteen trillion, one hundred twelve billion, one hundred twelve million, two hundred twenty thousand, thirty-one".