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141121140001243 is a prime number
BaseRepresentation
bin100000000101100101010011…
…011010111000100111011011
3200111200001022212221122021221
4200011211103122320213123
5121444112043320014433
61220050053504112511
741503444256045233
oct4005452332704733
9614601285848257
10141121140001243
1140a69159568046
12139b2280305737
13609888810b53c
1426bc42a22ccc3
15114ad40d4172d
hex8059536b89db

141121140001243 has 2 divisors, whose sum is σ = 141121140001244. Its totient is φ = 141121140001242.

The previous prime is 141121140000853. The next prime is 141121140001273. The reversal of 141121140001243 is 342100041121141.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 141121140001243 - 217 = 141121139870171 is a prime.

It is not a weakly prime, because it can be changed into another prime (141121140001273) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70560570000621 + 70560570000622.

It is an arithmetic number, because the mean of its divisors is an integer number (70560570000622).

Almost surely, 2141121140001243 is an apocalyptic number.

141121140001243 is a deficient number, since it is larger than the sum of its proper divisors (1).

141121140001243 is an equidigital number, since it uses as much as digits as its factorization.

141121140001243 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 768, while the sum is 25.

Adding to 141121140001243 its reverse (342100041121141), we get a palindrome (483221181122384).

The spelling of 141121140001243 in words is "one hundred forty-one trillion, one hundred twenty-one billion, one hundred forty million, one thousand, two hundred forty-three".