Base | Representation |
---|---|
bin | 100000000101100101010011… |
… | …011010111000100111011011 |
3 | 200111200001022212221122021221 |
4 | 200011211103122320213123 |
5 | 121444112043320014433 |
6 | 1220050053504112511 |
7 | 41503444256045233 |
oct | 4005452332704733 |
9 | 614601285848257 |
10 | 141121140001243 |
11 | 40a69159568046 |
12 | 139b2280305737 |
13 | 609888810b53c |
14 | 26bc42a22ccc3 |
15 | 114ad40d4172d |
hex | 8059536b89db |
141121140001243 has 2 divisors, whose sum is σ = 141121140001244. Its totient is φ = 141121140001242.
The previous prime is 141121140000853. The next prime is 141121140001273. The reversal of 141121140001243 is 342100041121141.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 141121140001243 - 217 = 141121139870171 is a prime.
It is not a weakly prime, because it can be changed into another prime (141121140001273) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70560570000621 + 70560570000622.
It is an arithmetic number, because the mean of its divisors is an integer number (70560570000622).
Almost surely, 2141121140001243 is an apocalyptic number.
141121140001243 is a deficient number, since it is larger than the sum of its proper divisors (1).
141121140001243 is an equidigital number, since it uses as much as digits as its factorization.
141121140001243 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 768, while the sum is 25.
Adding to 141121140001243 its reverse (342100041121141), we get a palindrome (483221181122384).
The spelling of 141121140001243 in words is "one hundred forty-one trillion, one hundred twenty-one billion, one hundred forty million, one thousand, two hundred forty-three".
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