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141121241431411 is a prime number
BaseRepresentation
bin100000000101100101011001…
…011101110011110101110011
3200111200001120221210211022211
4200011211121131303311303
5121444112300301301121
61220050111530112551
741503446630145063
oct4005453135636563
9614601527724284
10141121241431411
1140a6920084602a
12139b22aa27b757
1360988a3132ca7
1426bc4398b33a3
15114ad49bc9ce1
hex805959773d73

141121241431411 has 2 divisors, whose sum is σ = 141121241431412. Its totient is φ = 141121241431410.

The previous prime is 141121241431409. The next prime is 141121241431501. The reversal of 141121241431411 is 114134142121141.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 141121241431411 - 21 = 141121241431409 is a prime.

Together with 141121241431409, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (141121241431211) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70560620715705 + 70560620715706.

It is an arithmetic number, because the mean of its divisors is an integer number (70560620715706).

Almost surely, 2141121241431411 is an apocalyptic number.

141121241431411 is a deficient number, since it is larger than the sum of its proper divisors (1).

141121241431411 is an equidigital number, since it uses as much as digits as its factorization.

141121241431411 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 3072, while the sum is 31.

Adding to 141121241431411 its reverse (114134142121141), we get a palindrome (255255383552552).

The spelling of 141121241431411 in words is "one hundred forty-one trillion, one hundred twenty-one billion, two hundred forty-one million, four hundred thirty-one thousand, four hundred eleven".