1411214220131 has 2 divisors, whose sum is σ = 1411214220132. Its totient is φ = 1411214220130.

The previous prime is 1411214220109. The next prime is 1411214220181. The reversal of 1411214220131 is 1310224121141.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1411214220131 is a prime.

It is a super-2 number, since 2×1411214220131² (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1411214220097 and 1411214220106.

It is not a weakly prime, because it can be changed into another prime (1411214220181) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 705607110065 + 705607110066.

It is an arithmetic number, because the mean of its divisors is an integer number (705607110066).

Almost surely, 2^{1411214220131} is an apocalyptic number.

1411214220131 is a deficient number, since it is larger than the sum of its proper divisors (1).

1411214220131 is an equidigital number, since it uses as much as digits as its factorization.

1411214220131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 384, while the sum is 23.

Adding to 1411214220131 its reverse (1310224121141), we get a palindrome (2721438341272).

The spelling of 1411214220131 in words is "one trillion, four hundred eleven billion, two hundred fourteen million, two hundred twenty thousand, one hundred thirty-one".