Base | Representation |
---|---|
bin | 100000000101100110001101… |
… | …010100010000111100110111 |
3 | 200111200010211120200222122212 |
4 | 200011212031110100330313 |
5 | 121444121041001010224 |
6 | 1220050334123244035 |
7 | 41503510322243501 |
oct | 4005461524207467 |
9 | 614603746628585 |
10 | 141122111344439 |
11 | 40a69607898615 |
12 | 139b24b167961b |
13 | 60989b1423c24 |
14 | 26bc4bd23ad71 |
15 | 114ad9b261d0e |
hex | 80598d510f37 |
141122111344439 has 2 divisors, whose sum is σ = 141122111344440. Its totient is φ = 141122111344438.
The previous prime is 141122111344327. The next prime is 141122111344447. The reversal of 141122111344439 is 934443111221141.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 141122111344439 - 216 = 141122111278903 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 141122111344396 and 141122111344405.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (141122111344639) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70561055672219 + 70561055672220.
It is an arithmetic number, because the mean of its divisors is an integer number (70561055672220).
Almost surely, 2141122111344439 is an apocalyptic number.
141122111344439 is a deficient number, since it is larger than the sum of its proper divisors (1).
141122111344439 is an equidigital number, since it uses as much as digits as its factorization.
141122111344439 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 82944, while the sum is 41.
The spelling of 141122111344439 in words is "one hundred forty-one trillion, one hundred twenty-two billion, one hundred eleven million, three hundred forty-four thousand, four hundred thirty-nine".
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