Base | Representation |
---|---|
bin | 100000000101100110001101… |
… | …111001100010001100101101 |
3 | 200111200010212021002100112202 |
4 | 200011212031321202030231 |
5 | 121444121101001130123 |
6 | 1220050335112511245 |
7 | 41503510501264415 |
oct | 4005461571421455 |
9 | 614603767070482 |
10 | 141122121114413 |
11 | 40a6961236097a |
12 | 139b24b49ab525 |
13 | 60989b3464b8a |
14 | 26bc4c0661645 |
15 | 114ad9c041a28 |
hex | 80598de6232d |
141122121114413 has 2 divisors, whose sum is σ = 141122121114414. Its totient is φ = 141122121114412.
The previous prime is 141122121114349. The next prime is 141122121114421. The reversal of 141122121114413 is 314411121221141.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 140984585458249 + 137535656164 = 11873693^2 + 370858^2 .
It is a cyclic number.
It is not a de Polignac number, because 141122121114413 - 26 = 141122121114349 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (141122121114613) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70561060557206 + 70561060557207.
It is an arithmetic number, because the mean of its divisors is an integer number (70561060557207).
Almost surely, 2141122121114413 is an apocalyptic number.
It is an amenable number.
141122121114413 is a deficient number, since it is larger than the sum of its proper divisors (1).
141122121114413 is an equidigital number, since it uses as much as digits as its factorization.
141122121114413 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 1536, while the sum is 29.
Adding to 141122121114413 its reverse (314411121221141), we get a palindrome (455533242335554).
The spelling of 141122121114413 in words is "one hundred forty-one trillion, one hundred twenty-two billion, one hundred twenty-one million, one hundred fourteen thousand, four hundred thirteen".
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