141123130333051 has 4 divisors (see below), whose sum is σ = 141153869420704. Its totient is φ = 141092391245400.

The previous prime is 141123130333021. The next prime is 141123130333067. The reversal of 141123130333051 is 150333031321141.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 141123130333051 - 2⁵ = 141123130333019 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (141123130333021) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 15369536940 + ... + 15369546121.

It is an arithmetic number, because the mean of its divisors is an integer number (35288467355176).

Almost surely, 2^{141123130333051} is an apocalyptic number.

141123130333051 is a deficient number, since it is larger than the sum of its proper divisors (30739087653).

141123130333051 is an equidigital number, since it uses as much as digits as its factorization.

141123130333051 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 30739087652.

The product of its (nonzero) digits is 9720, while the sum is 31.

Adding to 141123130333051 its reverse (150333031321141), we get a palindrome (291456161654192).

The spelling of 141123130333051 in words is "one hundred forty-one trillion, one hundred twenty-three billion, one hundred thirty million, three hundred thirty-three thousand, fifty-one".