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1411231404103 = 4453731686719
BaseRepresentation
bin10100100010010011111…
…100100101000001000111
311222220122010212020110121
4110202103330211001013
5141110200214412403
63000151042402411
7203646426004303
oct24422374450107
94886563766417
101411231404103
114a4555378444
121a960a660407
13a3103762911
144c438114d03
1526a991ad3bd
hex14893f25047

1411231404103 has 4 divisors (see below), whose sum is σ = 1411263135360. Its totient is φ = 1411199672848.

The previous prime is 1411231404067. The next prime is 1411231404113. The reversal of 1411231404103 is 3014041321141.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1411231404103 - 29 = 1411231403591 is a prime.

It is a super-3 number, since 3×14112314041033 (a number of 37 digits) contains 333 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1411231404113) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 15798823 + ... + 15887896.

It is an arithmetic number, because the mean of its divisors is an integer number (352815783840).

Almost surely, 21411231404103 is an apocalyptic number.

1411231404103 is a deficient number, since it is larger than the sum of its proper divisors (31731257).

1411231404103 is an equidigital number, since it uses as much as digits as its factorization.

1411231404103 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 31731256.

The product of its (nonzero) digits is 1152, while the sum is 25.

Adding to 1411231404103 its reverse (3014041321141), we get a palindrome (4425272725244).

The spelling of 1411231404103 in words is "one trillion, four hundred eleven billion, two hundred thirty-one million, four hundred four thousand, one hundred three".

Divisors: 1 44537 31686719 1411231404103