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14112340454341 is a prime number
BaseRepresentation
bin1100110101011100100100…
…0010100010101111000101
31211222010102021022022220201
43031113021002202233011
53322204033124014331
650003041504530501
72654403644432053
oct315271102425705
954863367268821
1014112340454341
114551012307788
1216bb096320a31
137b4a322bb57c
1436b0804111d3
15197163708a61
hexcd5c90a2bc5

14112340454341 has 2 divisors, whose sum is σ = 14112340454342. Its totient is φ = 14112340454340.

The previous prime is 14112340454327. The next prime is 14112340454347. The reversal of 14112340454341 is 14345404321141.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 13292980570116 + 819359884225 = 3645954^2 + 905185^2 .

It is a cyclic number.

It is not a de Polignac number, because 14112340454341 - 25 = 14112340454309 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 14112340454341.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14112340454347) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7056170227170 + 7056170227171.

It is an arithmetic number, because the mean of its divisors is an integer number (7056170227171).

Almost surely, 214112340454341 is an apocalyptic number.

It is an amenable number.

14112340454341 is a deficient number, since it is larger than the sum of its proper divisors (1).

14112340454341 is an equidigital number, since it uses as much as digits as its factorization.

14112340454341 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 92160, while the sum is 37.

Adding to 14112340454341 its reverse (14345404321141), we get a palindrome (28457744775482).

The spelling of 14112340454341 in words is "fourteen trillion, one hundred twelve billion, three hundred forty million, four hundred fifty-four thousand, three hundred forty-one".