Base | Representation |
---|---|
bin | 1100110101011100110111… |
… | …0111000011110101101011 |
3 | 1211222010121220111020211222 |
4 | 3031113031313003311223 |
5 | 3322204214330032113 |
6 | 50003053514212255 |
7 | 2654405646034013 |
oct | 315271567036553 |
9 | 54863556436758 |
10 | 14112421330283 |
11 | 4551053a27001 |
12 | 16bb0b942408b |
13 | 7b4a45c97563 |
14 | 36b08b064c43 |
15 | 19716a881e08 |
hex | cd5cddc3d6b |
14112421330283 has 2 divisors, whose sum is σ = 14112421330284. Its totient is φ = 14112421330282.
The previous prime is 14112421330243. The next prime is 14112421330321. The reversal of 14112421330283 is 38203312421141.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 14112421330283 - 238 = 13837543423339 is a prime.
It is not a weakly prime, because it can be changed into another prime (14112421330243) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7056210665141 + 7056210665142.
It is an arithmetic number, because the mean of its divisors is an integer number (7056210665142).
Almost surely, 214112421330283 is an apocalyptic number.
14112421330283 is a deficient number, since it is larger than the sum of its proper divisors (1).
14112421330283 is an equidigital number, since it uses as much as digits as its factorization.
14112421330283 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 27648, while the sum is 35.
The spelling of 14112421330283 in words is "fourteen trillion, one hundred twelve billion, four hundred twenty-one million, three hundred thirty thousand, two hundred eighty-three".
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