Base | Representation |
---|---|
bin | 100000000101101000001101… |
… | …001101011011000111001111 |
3 | 200111200100101010012100100122 |
4 | 200011220031031123013033 |
5 | 121444134434300102303 |
6 | 1220051331053015155 |
7 | 41503614435305315 |
oct | 4005501515330717 |
9 | 614610333170318 |
10 | 141124257034703 |
11 | 40a6a508aa3458 |
12 | 139b29b01844bb |
13 | 6098c63b1b637 |
14 | 26bc6441bc0b5 |
15 | 114ae74801e38 |
hex | 805a0d35b1cf |
141124257034703 has 2 divisors, whose sum is σ = 141124257034704. Its totient is φ = 141124257034702.
The previous prime is 141124257034699. The next prime is 141124257034729. The reversal of 141124257034703 is 307430752421141.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 141124257034703 - 22 = 141124257034699 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (141124257034003) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70562128517351 + 70562128517352.
It is an arithmetic number, because the mean of its divisors is an integer number (70562128517352).
Almost surely, 2141124257034703 is an apocalyptic number.
141124257034703 is a deficient number, since it is larger than the sum of its proper divisors (1).
141124257034703 is an equidigital number, since it uses as much as digits as its factorization.
141124257034703 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 564480, while the sum is 44.
The spelling of 141124257034703 in words is "one hundred forty-one trillion, one hundred twenty-four billion, two hundred fifty-seven million, thirty-four thousand, seven hundred three".
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