Base | Representation |
---|---|
bin | 10100100010010100101… |
… | …010011000101001001111 |
3 | 11222220122222110022021021 |
4 | 110202110222120221033 |
5 | 141110211303141142 |
6 | 3000152152015011 |
7 | 203646633036010 |
oct | 24422452305117 |
9 | 4886588408237 |
10 | 1411243412047 |
11 | 4a456112a167 |
12 | 1a9612691467 |
13 | a31060a8401 |
14 | 4c43995d007 |
15 | 26a9a281267 |
hex | 14894a98a4f |
1411243412047 has 4 divisors (see below), whose sum is σ = 1612849613776. Its totient is φ = 1209637210320.
The previous prime is 1411243412027. The next prime is 1411243412063. The reversal of 1411243412047 is 7402143421141.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 1411243412047 - 223 = 1411235023439 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1411243412027) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 100803100854 + ... + 100803100867.
It is an arithmetic number, because the mean of its divisors is an integer number (403212403444).
Almost surely, 21411243412047 is an apocalyptic number.
1411243412047 is a deficient number, since it is larger than the sum of its proper divisors (201606201729).
1411243412047 is an equidigital number, since it uses as much as digits as its factorization.
1411243412047 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 201606201728.
The product of its (nonzero) digits is 21504, while the sum is 34.
Adding to 1411243412047 its reverse (7402143421141), we get a palindrome (8813386833188).
The spelling of 1411243412047 in words is "one trillion, four hundred eleven billion, two hundred forty-three million, four hundred twelve thousand, forty-seven".
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