Base | Representation |
---|---|
bin | 11010010010010101… |
… | …01100111001101101 |
3 | 1100102112001102202121 |
4 | 31021022230321231 |
5 | 212400241202023 |
6 | 10252210352541 |
7 | 1006501536433 |
oct | 151112547155 |
9 | 40375042677 |
10 | 14112444013 |
11 | 5a9211a078 |
12 | 289a28b751 |
13 | 143b9bb7b5 |
14 | 97c3c6d53 |
15 | 578e44d5d |
hex | 3492ace6d |
14112444013 has 2 divisors, whose sum is σ = 14112444014. Its totient is φ = 14112444012.
The previous prime is 14112443987. The next prime is 14112444113. The reversal of 14112444013 is 31044421141.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 12616456329 + 1495987684 = 112323^2 + 38678^2 .
It is a cyclic number.
It is not a de Polignac number, because 14112444013 - 25 = 14112443981 is a prime.
It is a super-2 number, since 2×141124440132 (a number of 21 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14112444113) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7056222006 + 7056222007.
It is an arithmetic number, because the mean of its divisors is an integer number (7056222007).
Almost surely, 214112444013 is an apocalyptic number.
It is an amenable number.
14112444013 is a deficient number, since it is larger than the sum of its proper divisors (1).
14112444013 is an equidigital number, since it uses as much as digits as its factorization.
14112444013 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1536, while the sum is 25.
Adding to 14112444013 its reverse (31044421141), we get a palindrome (45156865154).
The spelling of 14112444013 in words is "fourteen billion, one hundred twelve million, four hundred forty-four thousand, thirteen".
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