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14112514151321 is a prime number
BaseRepresentation
bin1100110101011101001101…
…1001001001001110011001
31211222010212101011001101012
43031113103121021032121
53322204412110320241
650003111031503305
72654411154016205
oct315272331111631
954863771131335
1014112514151321
1145510a1364903
1216bb124527b35
137b4a5c296551
1436b099507b05
15197173ab96eb
hexcd5d3649399

14112514151321 has 2 divisors, whose sum is σ = 14112514151322. Its totient is φ = 14112514151320.

The previous prime is 14112514151303. The next prime is 14112514151341. The reversal of 14112514151321 is 12315141521141.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 11874605862025 + 2237908289296 = 3445955^2 + 1495964^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-14112514151321 is a prime.

It is not a weakly prime, because it can be changed into another prime (14112514151341) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7056257075660 + 7056257075661.

It is an arithmetic number, because the mean of its divisors is an integer number (7056257075661).

Almost surely, 214112514151321 is an apocalyptic number.

It is an amenable number.

14112514151321 is a deficient number, since it is larger than the sum of its proper divisors (1).

14112514151321 is an equidigital number, since it uses as much as digits as its factorization.

14112514151321 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 4800, while the sum is 32.

Adding to 14112514151321 its reverse (12315141521141), we get a palindrome (26427655672462).

The spelling of 14112514151321 in words is "fourteen trillion, one hundred twelve billion, five hundred fourteen million, one hundred fifty-one thousand, three hundred twenty-one".