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14112514200041 is a prime number
BaseRepresentation
bin1100110101011101001101…
…1001010101000111101001
31211222010212101020112012122
43031113103121111013221
53322204412113400131
650003111032521025
72654411154311225
oct315272331250751
954863771215178
1014112514200041
1145510a1398474
1216bb124550175
137b4a5c2b278a
1436b09951b785
15197173ac8d7b
hexcd5d36551e9

14112514200041 has 2 divisors, whose sum is σ = 14112514200042. Its totient is φ = 14112514200040.

The previous prime is 14112514200007. The next prime is 14112514200049. The reversal of 14112514200041 is 14000241521141.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 13639940446441 + 472573753600 = 3693229^2 + 687440^2 .

It is a cyclic number.

It is not a de Polignac number, because 14112514200041 - 26 = 14112514199977 is a prime.

It is not a weakly prime, because it can be changed into another prime (14112514200049) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7056257100020 + 7056257100021.

It is an arithmetic number, because the mean of its divisors is an integer number (7056257100021).

Almost surely, 214112514200041 is an apocalyptic number.

It is an amenable number.

14112514200041 is a deficient number, since it is larger than the sum of its proper divisors (1).

14112514200041 is an equidigital number, since it uses as much as digits as its factorization.

14112514200041 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1280, while the sum is 26.

Adding to 14112514200041 its reverse (14000241521141), we get a palindrome (28112755721182).

The spelling of 14112514200041 in words is "fourteen trillion, one hundred twelve billion, five hundred fourteen million, two hundred thousand, forty-one".