Base | Representation |
---|---|
bin | 1100110101011101001111… |
… | …0000011000000110010000 |
3 | 1211222010212210121110121022 |
4 | 3031113103300120012100 |
5 | 3322204420140212202 |
6 | 50003111410215012 |
7 | 2654411256543035 |
oct | 315272360300620 |
9 | 54863783543538 |
10 | 14112520241552 |
11 | 45510a4844557 |
12 | 16bb126584468 |
13 | 7b4a60619635 |
14 | 36b09a25138c |
15 | 1971743bdea2 |
hex | cd5d3c18190 |
14112520241552 has 10 divisors (see below), whose sum is σ = 27343007968038. Its totient is φ = 7056260120768.
The previous prime is 14112520241527. The next prime is 14112520241623. The reversal of 14112520241552 is 25514202521141.
It can be written as a sum of positive squares in only one way, i.e., 9811027649536 + 4301492592016 = 3132256^2 + 2074004^2 .
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 441016257533 + ... + 441016257564.
Almost surely, 214112520241552 is an apocalyptic number.
It is an amenable number.
14112520241552 is a deficient number, since it is larger than the sum of its proper divisors (13230487726486).
14112520241552 is an equidigital number, since it uses as much as digits as its factorization.
14112520241552 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 882032515105 (or 882032515099 counting only the distinct ones).
The product of its (nonzero) digits is 32000, while the sum is 35.
Adding to 14112520241552 its reverse (25514202521141), we get a palindrome (39626722762693).
The spelling of 14112520241552 in words is "fourteen trillion, one hundred twelve billion, five hundred twenty million, two hundred forty-one thousand, five hundred fifty-two".
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