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14113003 = 16784509
BaseRepresentation
bin110101110101…
…100011101011
3222120000101211
4311311203223
512103104003
61222253551
7230646532
oct65654353
928500354
1014113003
117a6a343
1248872b7
132c019b8
141c35319
15138b96d
hexd758eb

14113003 has 4 divisors (see below), whose sum is σ = 14197680. Its totient is φ = 14028328.

The previous prime is 14112971. The next prime is 14113013. The reversal of 14113003 is 30031141.

14113003 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 30031141 = 74290163.

It is a cyclic number.

It is not a de Polignac number, because 14113003 - 25 = 14112971 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (14113013) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 42088 + ... + 42421.

It is an arithmetic number, because the mean of its divisors is an integer number (3549420).

Almost surely, 214113003 is an apocalyptic number.

14113003 is a deficient number, since it is larger than the sum of its proper divisors (84677).

14113003 is an equidigital number, since it uses as much as digits as its factorization.

14113003 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 84676.

The product of its (nonzero) digits is 36, while the sum is 13.

The square root of 14113003 is about 3756.7276984099. The cubic root of 14113003 is about 241.6609497392.

Adding to 14113003 its reverse (30031141), we get a palindrome (44144144).

The spelling of 14113003 in words is "fourteen million, one hundred thirteen thousand, three".

Divisors: 1 167 84509 14113003