141130102433 has 4 divisors (see below), whose sum is σ = 141131964720. Its totient is φ = 141128240148.

The previous prime is 141130102429. The next prime is 141130102459. The reversal of 141130102433 is 334201031141.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 141130102433 - 2² = 141130102429 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 141130102399 and 141130102408.

It is not an unprimeable number, because it can be changed into a prime (141130102933) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 812423 + ... + 970716.

It is an arithmetic number, because the mean of its divisors is an integer number (35282991180).

Almost surely, 2^141130102433 is an apocalyptic number.

It is an amenable number.

141130102433 is a deficient number, since it is larger than the sum of its proper divisors (1862287).

141130102433 is an equidigital number, since it uses as much as digits as its factorization.

141130102433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1862286.

The product of its (nonzero) digits is 864, while the sum is 23.

Adding to 141130102433 its reverse (334201031141), we get a palindrome (475331133574).

The spelling of 141130102433 in words is "one hundred forty-one billion, one hundred thirty million, one hundred two thousand, four hundred thirty-three".