14113031202331 has 2 divisors, whose sum is σ = 14113031202332. Its totient is φ = 14113031202330.

The previous prime is 14113031202229. The next prime is 14113031202359. The reversal of 14113031202331 is 13320213031141.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-14113031202331 is a prime.

It is a super-2 number, since 2×14113031202331² (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 14113031202296 and 14113031202305.

It is not a weakly prime, because it can be changed into another prime (14113031203331) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7056515601165 + 7056515601166.

It is an arithmetic number, because the mean of its divisors is an integer number (7056515601166).

Almost surely, 2^{14113031202331} is an apocalyptic number.

14113031202331 is a deficient number, since it is larger than the sum of its proper divisors (1).

14113031202331 is an equidigital number, since it uses as much as digits as its factorization.

14113031202331 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1296, while the sum is 25.

Adding to 14113031202331 its reverse (13320213031141), we get a palindrome (27433244233472).

The spelling of 14113031202331 in words is "fourteen trillion, one hundred thirteen billion, thirty-one million, two hundred two thousand, three hundred thirty-one".