Base | Representation |
---|---|
bin | 11010010010011001… |
… | …11111001110000100 |
3 | 1100102120011212212121 |
4 | 31021030333032010 |
5 | 212400414341312 |
6 | 10252231255324 |
7 | 1006506613633 |
oct | 151114771604 |
9 | 40376155777 |
10 | 14113043332 |
11 | 5a92499383 |
12 | 289a51a544 |
13 | 143bb6b51b |
14 | 97c50151a |
15 | 579012707 |
hex | 34933f384 |
14113043332 has 12 divisors (see below), whose sum is σ = 24700965660. Its totient is φ = 7055624576.
The previous prime is 14113043309. The next prime is 14113043359. The reversal of 14113043332 is 23334031141.
14113043332 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It can be written as a sum of positive squares in 2 ways, for example, as 11207186496 + 2905856836 = 105864^2 + 53906^2 .
It is a junction number, because it is equal to n+sod(n) for n = 14113043297 and 14113043306.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 188233 + ... + 252304.
It is an arithmetic number, because the mean of its divisors is an integer number (2058413805).
Almost surely, 214113043332 is an apocalyptic number.
It is an amenable number.
14113043332 is a deficient number, since it is larger than the sum of its proper divisors (10587922328).
14113043332 is a wasteful number, since it uses less digits than its factorization.
14113043332 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 448550 (or 448548 counting only the distinct ones).
The product of its (nonzero) digits is 2592, while the sum is 25.
Adding to 14113043332 its reverse (23334031141), we get a palindrome (37447074473).
The spelling of 14113043332 in words is "fourteen billion, one hundred thirteen million, forty-three thousand, three hundred thirty-two".
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