141130434341011 has 4 divisors (see below), whose sum is σ = 141846832485072. Its totient is φ = 140414036196952.

The previous prime is 141130434340963. The next prime is 141130434341021. The reversal of 141130434341011 is 110143434031141.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 141130434341011 - 2¹¹ = 141130434338963 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (141130434341021) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 358199071735 + ... + 358199072128.

It is an arithmetic number, because the mean of its divisors is an integer number (35461708121268).

Almost surely, 2^{141130434341011} is an apocalyptic number.

141130434341011 is a deficient number, since it is larger than the sum of its proper divisors (716398144061).

141130434341011 is an equidigital number, since it uses as much as digits as its factorization.

141130434341011 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 716398144060.

The product of its (nonzero) digits is 6912, while the sum is 31.

Adding to 141130434341011 its reverse (110143434031141), we get a palindrome (251273868372152).

The spelling of 141130434341011 in words is "one hundred forty-one trillion, one hundred thirty billion, four hundred thirty-four million, three hundred forty-one thousand, eleven".