14113110403330 has 8 divisors (see below), whose sum is σ = 25403598726012. Its totient is φ = 5645244161328.

The previous prime is 14113110403279. The next prime is 14113110403339. The reversal of 14113110403330 is 3330401131141.

It can be written as a sum of positive squares in 2 ways, for example, as 13603387228729 + 509723174601 = 3688277^2 + 713949^2 .

It is a sphenic number, since it is the product of 3 distinct primes.

It is a junction number, because it is equal to n+sod(n) for n = 14113110403295 and 14113110403304.

It is not an unprimeable number, because it can be changed into a prime (14113110403339) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 705655520157 + ... + 705655520176.

Almost surely, 2^{14113110403330} is an apocalyptic number.

14113110403330 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

14113110403330 is a deficient number, since it is larger than the sum of its proper divisors (11290488322682).

14113110403330 is a wasteful number, since it uses less digits than its factorization.

14113110403330 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1411311040340.

The product of its (nonzero) digits is 1296, while the sum is 25.

Adding to 14113110403330 its reverse (3330401131141), we get a palindrome (17443511534471).

The spelling of 14113110403330 in words is "fourteen trillion, one hundred thirteen billion, one hundred ten million, four hundred three thousand, three hundred thirty".