Search a number
-
+
141131134174477 is a prime number
BaseRepresentation
bin100000000101101110100111…
…000111101000010100001101
3200111201000010101202020121011
4200011232213013220110031
5121444243030322040402
61220054425322005221
741504250033111436
oct4005564707502415
9614630111666534
10141131134174477
1140a72417a62347
12139b41ab346811
1360997bb838805
1426bcad76b648d
15114b22844ced7
hex805ba71e850d

141131134174477 has 2 divisors, whose sum is σ = 141131134174478. Its totient is φ = 141131134174476.

The previous prime is 141131134174453. The next prime is 141131134174507. The reversal of 141131134174477 is 774471431131141.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 136369634863081 + 4761499311396 = 11677741^2 + 2182086^2 .

It is a cyclic number.

It is not a de Polignac number, because 141131134174477 - 223 = 141131125785869 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 141131134174477.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (141131134174417) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70565567087238 + 70565567087239.

It is an arithmetic number, because the mean of its divisors is an integer number (70565567087239).

Almost surely, 2141131134174477 is an apocalyptic number.

It is an amenable number.

141131134174477 is a deficient number, since it is larger than the sum of its proper divisors (1).

141131134174477 is an equidigital number, since it uses as much as digits as its factorization.

141131134174477 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 790272, while the sum is 49.

The spelling of 141131134174477 in words is "one hundred forty-one trillion, one hundred thirty-one billion, one hundred thirty-four million, one hundred seventy-four thousand, four hundred seventy-seven".