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1411311434147 is a prime number
BaseRepresentation
bin10100100010011000101…
…101110111100110100011
311222220211201110012001022
4110202120231313212203
5141110331211343042
63000203022000055
7203651420154116
oct24423055674643
94886751405038
101411311434147
114a459656a17a
121a963141602b
13a3117203884
144c4449c857d
1526aa121acd2
hex14898b779a3

1411311434147 has 2 divisors, whose sum is σ = 1411311434148. Its totient is φ = 1411311434146.

The previous prime is 1411311434119. The next prime is 1411311434153. The reversal of 1411311434147 is 7414341131141.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1411311434147 - 218 = 1411311172003 is a prime.

It is not a weakly prime, because it can be changed into another prime (1411311434107) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 705655717073 + 705655717074.

It is an arithmetic number, because the mean of its divisors is an integer number (705655717074).

Almost surely, 21411311434147 is an apocalyptic number.

1411311434147 is a deficient number, since it is larger than the sum of its proper divisors (1).

1411311434147 is an equidigital number, since it uses as much as digits as its factorization.

1411311434147 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 16128, while the sum is 35.

Adding to 1411311434147 its reverse (7414341131141), we get a palindrome (8825652565288).

The spelling of 1411311434147 in words is "one trillion, four hundred eleven billion, three hundred eleven million, four hundred thirty-four thousand, one hundred forty-seven".